2009-03-03

Primary and Secondary Current in Transformers

Although we can make the secondary voltage greater than the primary voltage in a transformer, this does not mean energy is created. Energy is still conserved.

In an ideal transformer, there is no loss of energy. Hence,

Power supplied to the primary coil = Power used in the secondary coil

That is,

VpIp = VsIs

Vp = Primary voltage , Ip = Primary current

Vs = Secondary voltage, Is = Secondary current

(Remember, Power, P = IV)

Which brings us to the ratio of current which is

Is / Ip = Vp / Vs

This means that if the voltage is stepped-up, the current in the secondary coil is stepped-down by the same ratio.

Comparing the transformer equation.

Vs / Vp = Ns / Np

We ultimately get

Is / Ip = Np / Ns

(Ns = number of coils in secondary coil)

(Np = number of coils in primary coil)

5 comments:

  1. i need clarity over ohm's law and the relation posted in this topic

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  2. I need clarity over ohm's law and the relation existing in your post over voltage-current relationship

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  3. Hi Lokesh, why u confuse this formula with ohms law. ohms law involved with resistance. Transformers involved with No. Of coil turns

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  4. Transformer ratings are in KVA so no impedance

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