In an ideal transformer, there is no loss of energy. Hence,

Power supplied to the primary coil = Power used in the secondary coil

That is,

VpIp = VsIs

Vp = Primary voltage , Ip = Primary current

Vs = Secondary voltage, Is = Secondary current

(Remember, Power, P = IV)

Which brings us to the ratio of current which is

Is / Ip = Vp / Vs

This means that if the voltage is stepped-up, the current in the secondary coil is stepped-down by the same ratio.

Comparing the transformer equation.

Vs / Vp = Ns / Np

We ultimately get

Is / Ip = Np / Ns

(Ns = number of coils in secondary coil)

(Np = number of coils in primary coil)

## 5 comments:

i need clarity over ohm's law and the relation posted in this topic

I need clarity over ohm's law and the relation existing in your post over voltage-current relationship

Hi Lokesh, why u confuse this formula with ohms law. ohms law involved with resistance. Transformers involved with No. Of coil turns

it is good

Transformer ratings are in KVA so no impedance

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