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2020-04-19
Solving problems, questions, calculations, linear motion 1
1. A car moves in a straight line from a static state to a state of constant acceleration. After 1000 m, the car achieves a velocity of 240 m/s. Calculate
i) the acceleration of the car
ii) time taken
iii) the velocity at t= 2 s.
Answer:
From the question the information we can get is
a = 0 m/s
v = 240 m/s
s = 1000 m
i) For acceleration
We can use the formula v^2 = u^2 + 2as
Refer to (http://fiziknota.blogspot.com/2020/04/linear-motion-formula.html)
^2 is squared
When we rearrange the formula we get
a = (v^2 - u^2) / 2s
= 240^2 - 0^2 / (2 x 1000)
= 28.8 ms^-2
ii) for time
We have to rearrange v = u + at
t = (v - u)/ a
= (240) / 28.8
= 8.33 s
iii) velocity at t = 2 s.
Using v = u + at
v = 0 + (28.8 x 2)
v = 57.6 m/s
Labels:
calculations,
linear motion 1,
questions,
Solving problems
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