Linear motion calculation 2
A bike has to move along a straight road. It starts from rest and then moves with uniform acceleration. After moving a distance of 100 m, it achieves a velocity of 120 m s^-1.
Find:
a) the bike acceleration
b) the time taken
c) the bike's velocity when t= 3s
SOLUTION
For question A)
Extract all the information that are needed.
u = 0 m/s
v = 120 m/s
s =100 m
What you need to find is the acceleration.
However there are several linear motion equation that needs to be considered.
1. a = (v -u)/t
2. s = 1/2 (u +v) t
3. s = ut + 1/2(at^2)
4. v^2 = u^2 + 2as
So we choose this equation v^2 = u^2 + 2as, because we have v, u and s.
rearrange the equation, we will get
a = (v^2 - u^2)/2s
= (120^2 - 0^2) / 2 (100)
= 72 m/s^2
For question B)
using a = (v - u) / t
rearrange the equation and you will get
t = (v -u)/ a
= (120 -0) / 72
= 5/3 s
For question C)
we need to find v,
so the equation that is most suitable is
v = u + at
= 0 + 72 (3)
= 216 m/s
Hope everything makes sense!
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2013-12-09
2013-12-08
Linear Motion Calculation Examples
A bicycle moved from point A and then moved 50 m to the north in 60 seconds. The bicycle then moved 120 m to the east in 40 seconds. Finally, it stopped. Calculate the
1. Total distance moved by the bicycle
2. Displacement
3. Velocity
4. Average speed
5. Speed of the bicycle when it is moving to the north
Solution:
1. Total distance = 50m + 170m
= 170m
2. Displacement
Remember displacement is the shortest distance between two points.
Imagine A as the beginning of a triangle. Then connect it with a line of 50m upwards then it turns left 120m (go east). so the distance is the hypotenuse.
Using Pythagoras' theorem = Squared root (120^2 + 50^2)
= 130m
3. Velocity = Displacement / time
= 130 m / 100 s
= 1.3 m s^-1
4. Average speed of the bicycle = total distance / total time
= 170m/ 100s
= 1.7 m s^-1
5. Speed = distance / time
Distance = 50m, time = 60s
= 50m / 60s
= 0.83 ms^-1
Be careful during calculation as most of the time Physics requires a good skill in maths!!
1. Total distance moved by the bicycle
2. Displacement
3. Velocity
4. Average speed
5. Speed of the bicycle when it is moving to the north
Solution:
1. Total distance = 50m + 170m
= 170m
2. Displacement
Remember displacement is the shortest distance between two points.
Imagine A as the beginning of a triangle. Then connect it with a line of 50m upwards then it turns left 120m (go east). so the distance is the hypotenuse.
Using Pythagoras' theorem = Squared root (120^2 + 50^2)
= 130m
3. Velocity = Displacement / time
= 130 m / 100 s
= 1.3 m s^-1
4. Average speed of the bicycle = total distance / total time
= 170m/ 100s
= 1.7 m s^-1
5. Speed = distance / time
Distance = 50m, time = 60s
= 50m / 60s
= 0.83 ms^-1
Be careful during calculation as most of the time Physics requires a good skill in maths!!
Labels:
Displacement,
Distance,
linear motion calculation,
speed,
Velocity
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