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Showing posts with label Solving problems. Show all posts
Showing posts with label Solving problems. Show all posts
2020-04-23
Solving problems, questions, calculations, linear motion 2
Look at the diagram above. It is a displacement-time graph for a moving object.
Questions:
a) What is the displacement of the object at t = 2 s?
Answer = 20 m
b) When does the object cease to move?
Answer = From t = 4 s until t = 8 s
c) When does the object starts to move in the opposite direction?
Answer = At t = 8 s.
d) What is the velocity of the object at time
i) t = 6 s?
Answer = the object is not moving at all, hence velocity is zero.
ii) t = 9 s?
Gradient of the graph, as t = 9 is in the middle of the movement.
Hence v = - 40 / 2 = - 20 m/s
* Note the negative sign which indicates that the object is moving in the opposite direction.
e) Calculate the total distance traveled?
40m + 80m = 120 m, note that the direction of the movement does not matter here as distance is a scalar quantity.
f) Calculate the total displacement traveled?
+40m = ( - 80m) = -40m
Note that the total displacement is negative indicating the final position is -40m opposite the first direction of travel.
g) What is the average speed of the object?
Average speed = distance / time
= 120 / 12 = 10 m/s
h) What is the average velocity of the object
Average velocity = total displacement / time
= -40 / 12
= 3.33 m/s
Labels:
calculations,
Linear Motion,
questions,
Solving problems
2020-04-19
Solving problems, questions, calculations, linear motion 1
1. A car moves in a straight line from a static state to a state of constant acceleration. After 1000 m, the car achieves a velocity of 240 m/s. Calculate
i) the acceleration of the car
ii) time taken
iii) the velocity at t= 2 s.
Answer:
From the question the information we can get is
a = 0 m/s
v = 240 m/s
s = 1000 m
i) For acceleration
We can use the formula v^2 = u^2 + 2as
Refer to (http://fiziknota.blogspot.com/2020/04/linear-motion-formula.html)
^2 is squared
When we rearrange the formula we get
a = (v^2 - u^2) / 2s
= 240^2 - 0^2 / (2 x 1000)
= 28.8 ms^-2
ii) for time
We have to rearrange v = u + at
t = (v - u)/ a
= (240) / 28.8
= 8.33 s
iii) velocity at t = 2 s.
Using v = u + at
v = 0 + (28.8 x 2)
v = 57.6 m/s
Labels:
calculations,
linear motion 1,
questions,
Solving problems
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